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Question
Propan-1-ol can be prepared from propene by alcohol
Propan-1-ol can be prepared from propene by alcohol
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Solution
The correct option is C B2H6 followed by H2O2
When propene reacts with mercuric acetate followed by NaBH4, it gives secondary or tertiary alcohols, in accordance with Markownikoff’s rule. But, with diborane followed by H2O2, it gives primary alcohols which is in accordance with Anti-Markownikoff’s rule. 6CH3−CH=CH2+B2H6H2O2−−−→CH3−CH2−CH2OH
When propene reacts with mercuric acetate followed by NaBH4, it gives secondary or tertiary alcohols, in accordance with Markownikoff’s rule. But, with diborane followed by H2O2, it gives primary alcohols which is in accordance with Anti-Markownikoff’s rule. 6CH3−CH=CH2+B2H6H2O2−−−→CH3−CH2−CH2OH
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