Propane cannot be prepared from which reaction-

C H_{3} - C H = C H_{2} B_{2} H_{6} - -- \to O H^{-}

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C H_{3} C H_{2} C H_{2} I H I - - \to P

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C H_{3} C H_{2} C H_{2} C l N a ⟶

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None of these

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Solution

The correct option is A $C H_{3} - C H = C H_{2} B_{2} H_{6} - -- \to O H^{-}$
a Hydroboration of alkenes followed by hydrolysis in basic medium yield alcohols and not the alkanes.

$R - C H = C H_{2} B_{2} H_{6} ⟶ (R - C H_{2} - C H_{2})_{3} - B O H^{-} ⟶ R - C H_{2} - C H_{2} O H$

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Propane can be best prepared by the reaction

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