$P r o p a n e ⟶ 2 - I o d o p r o p a n e$
Best reagent for above conversion is:

I_{2} / h v

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N a l / a c e t o n e

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F_{2} / h v, N a l / a c e t o n e

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B r_{2} / h v, N a l / a c e t o n e

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Solution

The correct option is D $B r_{2} / h v, N a l / a c e t o n e$
$I_{2} / s u n l i g h t$ reaction is not possible in nature for preparation of iodopropane. So we first convert propane to 2- bromopropane and then by NaI/acetone to convert it into 2-iodopropane.

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Similar questions

2

R - C l + N a l D r y - ---- \to A c e t o n e R - I + N a C l

For the given reaction

$R - C l + N a l a c e t o n e - --- \to R - I + N a C l$

Which alkyl chloride will give maximum yield?

\begin{matrix} E r y t h r o - 2, 3 - d i b r o m o b u t a n e & N a l / A c e t o n e - ------- \to & (B) & C o l d a l k . - ---- \to K M n O_{4} & (C) (A) \end{matrix}

C H_{3} - C H = C H_{2} C l_{2} - - \to h v (A) N a I - -- \to a c e t o n e (B)

(B)

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