Propanoic acid is greater than formic acid (methanoic acid) by:

C H_{2}

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C_{3} H_{6}

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C_{2} H_{4}

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none of the above

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Solution

The correct option is C $C_{2} H_{4}$
Molecular formula of methanoic acid is $C H_{2} O_{2}$ it's structural formula is $H C O O H$ whereas molecular formula of propionic acid is $C_{3} H_{6} O_{2}$ it's structural formula is $C H_{3} C H_{2} C O O H$ . It is clear from the both formulas that propionic acid is greater by methanoic acid by $C_{2} H_{4}$

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