Propanoic acid reacts with chlorine ( $1$ eq.) in the presence of small amount of red phosphorus to give

Propanoyl chloride

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2 -

chloropropanoic acid

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Propanal

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Propanol

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Solution

The correct option is B $2 -$ chloropropanoic acid
Carboxylic acids having an $α -$ hydrogen are halogenated at the $α -$ position on treatment with chlorine or bromine in the presence of small amount of red phosphorus to give $α -$ halocarboxylic acids. The reaction is known as Hell-Volhard-Zelinsky reaction.
So, propanoic acid reacts with chlorine ( $1$ eq.) in presence of red phosporous gives $2 -$ chloropropanoic acid.

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Propanoic acid reacts with chlorine (1 eq.) in the presence of small amount of red phosphorus to give

Propanoic acid reacts with chlorine ( $1$ eq.) in the presence of small amount of red phosphorus to give