Propene $C H_{3} - C H = C H_{2}$ can be converted into propanol -1 by oxidation. Indicate which set of reagents amongst the following is ideal to bring the above conversion.

\frac{O_{3}}{Z n d u s t}

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B_{2} H_{6}

and alkaline

H_{2} O_{2}

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alkaline

K M n O_{4}

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O_{8} O_{4}

followed by

\frac{N a H S O_{3}}{a l c o h o l}

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Solution

The correct option is B $B_{2} H_{6}$ and alkaline $H_{2} O_{2}$
Hydroboration oxidation follows antimarkonikov’s rule, propene give 1 - propanol

Suggest Corrections

Similar questions

C H_{3} - C H = C H_{2}

C H_{3} - C H = C H_{2}

1

Propene, CH₃-CH=CH₂ can be converted to 1-propanol by oxidation. Which set of reagents among the following is

ideal to effect the conversion [CBSE PMT 1991]

R C H = C H_{2}

B_{2} H_{6}

H_{2} O_{2}

C H_{3} - C H = C H_{2}

B_{2} H_{6}

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