Propene $(C H_{3} - C H = C H_{2})$ can be transformed to compound (a to j) listed in the left-hand column.
Write letter designating the reagent, you believe will achieve desired transformation. In the case of a multi step sequence, write the reagent in the order they are to be used.

Desired product No. of Steps Write options
Reagent List
a. $C H_{3} C H B r C H_{2} B r$ one
A. $H g (O A c)_{2}$ in $H_{2} O$
b. $(C H_{3})_{2} C H O H$ two
B. $B_{2} H_{6}$ in THF
c. $C H_{3} C H_{2} C H_{2} O H$ two
C. $N a B H_{4}$ in alcohol
d. $C H_{3} C O C H_{3}$ three
D. $B r_{2}$ in $C H_{2} C l_{2}$
e. $C H_{3} C H_{2} C H O$ three
E. $H_{2} O_{2}$ in aqueous base
f. $C H_{3} C H (O H) C H_{2} B r$ one
F. HOBr(NBS in aqueous acetone)
g. $(C H_{3})_{2} C H B r$ one
G. HBr in $C H_{2} C l_{2}$
h. $C H_{3} C H (O H) C H_{2} O H$ two
H. $O s O_{4}$ in ether
i. $C H_{3} - C H_{2} - C H_{2} - C l$ three
I. Thionyl chloride $(S O C l_{2})$
j. $C H_{3} - C \equiv C H$ two
J. $N a H S O_{3}$ in aqueous acetone
K. NaOH in alcohol and reflux
L. $N a N H_{2}$ (strong base)

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Solution

Solution:-

Desired product No. of Steps Write options Reagent
a. $C H_{3} B r | C H C H_{2} B r$ one $D$ A. $H g {(O A c)}_{2}$ in $H_{2} O$
b. ${(C H_{3})}_{2} C H O H$ two $A \to C$ B. $B_{2} H_{6}$ in THF
c. $C H_{3} C H_{2} C H_{2} O H$ two $B \to E$ C. $N a B H_{4}$ in alcohol
d. $C H_{3} C O C H_{3}$ three $A \to C \to F$ D. ${B r}_{2}$ in $C H_{2} {C l}_{2}$
e. $C H_{3} C H_{2} C H O$ three $B \to E \to F$ E. $H_{2} O_{2}$ in aqueous base
f. $C H_{3} O H | C H C H_{2} B r$ one $F$ F. $H O B r$ ( $N B S$ in aqueous state)
g. ${(C H_{3})}_{2} C H B r$ one $G$ G. $H B r$ in $C H_{2} {C l}_{2}$
h. $C H_{3} O H | C H C H_{2} O H$ two $H \to J$ H. $O s O_{4}$ in ether
i. $C H_{3} C H_{2} C H_{2} C l$ three $B \to E \to I$ I. Thionyl chloride
j. $C H_{3} - C \equiv C H$ two $D \to L$ J. $N a H S O_{3}$ in aqueous acetone
K. $N a O H$ in alcohol and reflux
L. $N a N H_{2}$ (Strong base)

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Similar questions

Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

and

C H \equiv C H

is:

C H_{3} - C H_{2} - \oplus C H_{2}

C H_{3} - C H | F - \oplus C H_{2}

C H_{3} - C H | B r - \oplus C H_{2}

C H_{3} - C H | C l - \oplus C H_{2}

Arrange the following carbocations in decreasing order of their stability:

Q. Which is the most suitable reagent for the following transformation?

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

Propene $C H_{3} - C H = C H_{2}$ can be converted into propanol -1 by oxidation. Indicate which set of reagents amongst the following is ideal to bring the above conversion.

Q. The correct order of C - H bond length in

C H_{3} - C H_{3}, C H_{2} = C H_{2}

and

C H \equiv C H

is:

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	Desired product	No. of Steps	Write options		Reagent List
a.	$C H_{3} C H B r C H_{2} B r$	one		A.	$H g (O A c)_{2}$ in $H_{2} O$
b.	$(C H_{3})_{2} C H O H$	two		B.	$B_{2} H_{6}$ in THF
c.	$C H_{3} C H_{2} C H_{2} O H$	two		C.	$N a B H_{4}$ in alcohol
d.	$C H_{3} C O C H_{3}$	three		D.	$B r_{2}$ in $C H_{2} C l_{2}$
e.	$C H_{3} C H_{2} C H O$	three		E.	$H_{2} O_{2}$ in aqueous base
f.	$C H_{3} C H (O H) C H_{2} B r$	one		F.	HOBr(NBS in aqueous acetone)
g.	$(C H_{3})_{2} C H B r$	one		G.	HBr in $C H_{2} C l_{2}$
h.	$C H_{3} C H (O H) C H_{2} O H$	two		H.	$O s O_{4}$ in ether
i.	$C H_{3} - C H_{2} - C H_{2} - C l$	three		I.	Thionyl chloride $(S O C l_{2})$
j.	$C H_{3} - C \equiv C H$	two		J.	$N a H S O_{3}$ in aqueous acetone
				K.	NaOH in alcohol and reflux
				L.	$N a N H_{2}$ (strong base)