Propene on oxidation with diborane in presence of alkaline hydrogen peroxide gives.

Propan-

1

-ol

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Propan-

2

-ol

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Allyl alcohol

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Propan-

1

2

-diol

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Solution

The correct option is A Propan- $1$ -ol
Propene on oxidation with diborane in presence of alkaline hydrogen peroxide gives propan-1-ol
$C H_{3} - C H = C H_{2} (i) B_{2} H_{6} - -------- \to (i i) H_{2} O_{2} \cdot O H^{-} C H_{3} - C H_{2} - C H_{2} - O H$
Hydration follows anti-Markownikoff's rule. A molecule of water is added to double bond. Hydroxyl group is added to least substituted C atom.

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