Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little P, the product formed is

Ethane

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Propane

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Butane

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None of these

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Solution

The correct option is B
Propane

We know,

Alkanes can be prepared from reduction of acid and carbonyl compounds in presence of Red P + Ni

$(b) C H_{3} - C H_{2} - C O O H + 6 H l R e d P - -- \to$

$P r o p a n o i c a c i d$

$C H_{3} - C H_{2} - C H_{3} + 2 H_{2} O + \frac{3}{2}$

$P r o p a n e$

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Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little P, the product formed is

H I

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