Propionic acid with ${B r}_{2} / P$ yields a dibromaproduct. Its structure would be:

{C H}_{2} B r {C H}_{2} C O B r

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{C H}_{2} B r C H B r C O O H

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C H {B r}_{2} {C H}_{2} C O O H

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{C H}_{3} C {B r}_{2} C O O H

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Solution

The correct option is D ${C H}_{3} C {B r}_{2} C O O H$
$C H_{3} - C H_{2} - C O O H P r o p i o n i c a c i d$ $B r_{2} / P - --- \to C H_{3} - C (B r)_{2} - C O O H$

Carbonylic acids reacts with $C l_{2}$ or $B r_{2}$ in presence of red $P$ to give exclusively α-chloro or α -bromo acids. This reaction is called Hell-Volhard-Zelinsky (HVZ) reduction . This reaction is example of α H-substitution.
Hence option (D) is correct.

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Similar questions

C H_{3} C H_{2} C O O H S O C l_{2} - --- \to B N H_{3} - -- \to C K O H - -- \to B r_{2} D

D

C H_{3} C H_{2} C O O H S O C l_{2} \to B N H_{3} \to C K O H - -- \to B r_{2} D

D

C H_{3} C H_{2} C O O H S O C I_{2} - --- \to B N H_{3} - -- \to C B r_{2} + K O H - ------ \to D

C H_{3} C H_{2} C O O H S O C l_{2} - --- \to A C_{6} H_{6} - ----- \to A n h y . A l C l_{3} B H C N - -- \to C H O H - -- \to D

Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little P, the product formed is

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