Propyl ester reacts with isopropyl magnesium bromide to give $2^{o}$ alcohol. The ester is:

propyl methanoate

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isopropyl formate

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propyl ethanoate

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isopropyl ethanoate

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Solution

The correct option is C propyl methanoate
Therefore, to form a secondary alcohol, the ester should be propyl methanoate which is also known as propyl formate

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3^{o}

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