Propylsulphinic acid is prepared by the reaction of the following, followed by hydrolysis:

C_{3} H_{7} M g B r + {S O}_{2}

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C_{2} H_{5} M g B r + {S O}_{2}

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C_{3} H_{7} M g B r + {S O}_{3}

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C_{2} H_{5} M g B r + {S O}_{3}

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Solution

The correct option is B $C_{3} H_{7} M g B r + {S O}_{2}$
Propylsulphinic acid is prepared by the reaction of the
$C_{3} H_{7} M g B r + O = S = O \to C_{3} H_{7} S (= O) O M g B r H_{2} O / H^{+} \to C_{3} H_{7} - S (= O) - O H$

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