Propyne PIdentify the product P-

The correct option is C CH_3 O||C CH_3 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Acidity of Carboxylic Acids

Propyne PId...

Question

Propyne $H g S O_{4} + H_{2} S O_{4} (1 %) - ----------- \to P$

Identify the product P.

C H_{3} C H_{2} C H = O

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C H_{3} - C | | O - C H_{3}

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C H_{3} - C H_{2} - C H_{2} S O_{3} H

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C H_{3} C H_{2} C H_{3}

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{C H}_{3} - {C H}_{2} - O ∥ C - {C H}_{2} - {C H}_{2} - {C H}_{3}

{C H}_{3} - O ∥ C - {C H}_{3} | C | {C H}_{3} - {C H}_{3}

i) C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - O = C H_{2} - C H_{3}

i i) C H_{3} - C H_{2} - C H_{2} - O - C H_{3} | C | C H_{3} - C H_{3}

C H_{3} - C H_{3} | C = O

C H_{2} = P P h_{3} D M S O - --- \to C H_{3} - C H_{3} | C = C H_{2} + P h_{3} P = O

C H_{3} - C H_{2} - O | | C - C H_{2} - C H_{3}

C H_{3} - C H_{3} | C | C H_{3} - C H = C H_{2}

(i) H g (O A c)_{2}, H_{2} O - ---------- \to (i i) N a B H_{4} P

P

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