Prove- 1 - 2-1 - cos ec- - cos ec-

Now, 1 + ^2α1 + cos ecα = 1 + ^2α(cos ec α 1) 1 + cos ec^2α = 1 + ^2α(cos ec α 1) ^2α [ Since cos ec^2 α ^2 α=1 ] =1+cos ec α ...

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Apollonius's Theorem

Prove:- 1 + ...

Question

Prove:-
$1 + \frac{{cot}^{2} α}{1 + cos e c α} = cos e c α$

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Solution

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1 + \frac{{cot}^{2} α}{1 + csc α}

cos e c α

1 + \frac{c o t^{2} α}{1 + c o s e c α} = c o s e c α

{cot}^{2} α = 1 + a^{2}

cosec α + {cot}^{3} α sec α =

c o s e c α + c o t α = p,

c o s α = \frac{p^{2} - 1}{p^{2} + 1} .

\frac{1 + sin α}{1 + cos α} . \frac{1 + sec α}{1 + cosec α} = tan α .

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