Prove ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$

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Solution

we know
$\Rightarrow (a + b)^{2} = a (a + b) + b (a + b) = a^{2} + a b + b^{2} + a b = a^{2} + b^{2} + 2 a b$

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