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Question

Prove ∣ ∣x+42x2x2xx+42x2x2xx+4∣ ∣=(5x+4)(4x)2.

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Solution

Given:

∣ ∣x+42x2x2xx+42x2x2xx+4∣ ∣

Use operation: R1=R1+R2+R3

∣ ∣5x+45x+45x+42xx+42x2x2xx+4∣ ∣

Take common 5x+4.

(5x+4)∣ ∣1112xx+42x2x2xx+4∣ ∣

Use operation: R2=R2R3

(5x+4)∣ ∣11104xx42x2xx+4∣ ∣

Take determinant with respect to first column.

=1(16x22x2+8x)2x(4xx+4)

=1(163x2+8x)2x(82x)

=163x2+8x16x+4x2

=168x+x2

=(4x)2

Thus, ∣ ∣x+42x2x2xx+42x2x2xx+4∣ ∣=(5x+4)(4x)2


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