Prove by Mathematical Induction- for all n - N 12-22-32-n2-nn-12n-16

Given, [ 1^ 2 + 2^ 2 + 3^ 2 +.......+ K^ 2 +( K+1 ) ^ 2; =( k+1 ) ( k+2 ) ( 2k+3 ) #160; / 6 #160; ] ...

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Logarithmic Differentiation

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Question

Prove by Mathematical Induction, for all $n \in N$ $1^{2} + 2^{2} + 3^{2} + . . . . . . . n^{2} = \frac{n (n + 1) (2 n + 1)}{6}$

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1^{2} + 2^{2} + 3^{2} + . . . . + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

n \in

1^{2} + 2^{2} + 3^{2} + . . . + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

1^{+} 2^{2} + 3^{2} + . . . . + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

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1^{2} + 2^{2} + 3^{2} + 4^{2} + . . . . + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

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1^{2} + 2^{2} + 3^{2} + 4^{2} + \dots + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

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