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Byju's Answer
Standard XII
Mathematics
Differentiation of Inverse Trigonometric Functions
Prove cos 2...
Question
Prove
cos
2
θ
+
cos
2
(
θ
+
120
)
+
cos
2
(
θ
−
120
)
=
3
2
Open in App
Solution
cos
2
θ
+
cos
2
(
θ
+
120
)
+
cos
2
(
θ
−
120
)
=
1
+
cos
2
θ
2
+
1
+
cos
(
2
θ
+
240
)
2
+
1
+
cos
(
2
θ
−
240
)
2
=
3
2
+
1
2
[
cos
2
θ
+
cos
(
2
θ
+
240
)
+
cos
(
2
θ
−
240
)
]
=
3
2
+
1
2
[
cos
2
θ
+
2
cos
2
θ
cos
240
]
=
3
2
+
1
2
[
cos
2
θ
+
2
cos
2
θ
cos
(
180
+
60
)
]
=
3
2
+
1
2
[
cos
2
θ
−
2
cos
2
θ
cos
60
]
=
3
2
+
1
2
[
cos
2
θ
−
cos
2
θ
]
=
3
2
+
0
=
3
2
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