Prove cos A cos2A cos 4A cos 8A - sin16 A16 sin A

LHS=(2sinA cosA cos2A cos4A #10;cos8A/2sinA) =(2×>sin2A cos2A cos4A cos8A/2× 2sinA) =(2×>sin4A #10;cos4A cos8A/2× 4sinA) =(2× sin8A c ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of Trigonometric Ratios in Terms of Their Product

Prove cos A...

Question

Prove $cos A cos 2 A cos 4 A cos 8 A = \frac{sin 16 A}{16 sin A}$

Open in App

Solution

Suggest Corrections

Similar questions

cosA cos 2 A cos 4 A cos 8 A = \frac{sin 16 A}{16 sinA}

cos a cos 2 a \cdot cos 4 a cos 8 a = \frac{sin 16 a}{16 sin a}

Prove that cos A 2A cos 4A cos 8A = $\frac{s i n 16 A}{16 s i n A}$ .

A

π

cos A . cos 2 A . cos 4 A . cos 8 A = \frac{sin 16 A}{k sin A}

{sec}^{4} A - {sec}^{2} A = {tan}^{4} A + {tan}^{2} A

Join BYJU'S Learning Program