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Question

Prove :sinA1+cosA+1+cosAsinA=2cosecA.

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Solution

sinA1+cosA+1+cosAsinA=2cosecA
LHS : - sin2A+(1+cosA)2sinA(1+cosA)=sin2A+1+cos2+2cosAsinA+sinAcosA
=1+1+2cosAsinA(1+cosA) [sin2A+cos2A=1]
=2(1+cosA)sinA(1+cosA)
=2sinA
2cosecA=R.H.S.
Hence, LHS = RHS

1210522_1035995_ans_ff178948fadd4c1a9952404e0bc692c3.jpg

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