Prove - sin A - sin 3A - sin 5A - sin 7Acos- - cos 3- - cos 5- - cos 7- - tan 4A

LHS = #160; #10; sinA + sin 3A + sin 5A + sin 7A cos A + cos 3 A + #10; cos 5A + cos 7A #10; #10; = ( sin A + sin 7A) + ( sin #10 ...

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Trigonometric Ratios of Common Angles

Prove - sin...

Question

Prove -
$\frac{sin A + sin 3 A + sin 5 A + sin 7 A}{cos θ + cos 3 θ + cos 5 θ + cos 7 θ} = tan 4 A$

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\frac{cos 3 θ + 2 cos 5 θ + cos 7 θ}{cos θ + 2 cos 3 θ + cos 5 θ} = cos 2 θ - sin 2 θ tan 3 θ

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