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Byju's Answer
Standard XII
Mathematics
Basic Trigonometric Identities
Prove : tan...
Question
Prove :
tan
3
θ
1
+
tan
2
θ
+
cot
3
θ
1
+
cot
2
θ
=
1
−
2
sin
2
θ
cos
2
θ
sin
θ
cos
θ
.
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Solution
tan
3
θ
1
+
tan
2
θ
+
cot
3
θ
1
+
cot
2
θ
=
tan
3
θ
sec
2
θ
+
cot
3
θ
cos
e
c
2
θ
=
sin
3
θ
cos
3
θ
1
cos
2
θ
+
cos
3
θ
sin
3
θ
1
sin
2
θ
=
sin
3
θ
cos
θ
+
cos
3
θ
sin
θ
=
sin
4
θ
+
cos
4
θ
cos
θ
sin
θ
=
(
sin
2
θ
)
2
+
(
cos
2
θ
)
2
+
2
sin
2
θ
cos
2
θ
−
2
sin
2
θ
cos
2
θ
cos
θ
sin
θ
=
(
sin
2
θ
+
cos
2
θ
)
2
−
2
sin
2
θ
cos
2
θ
cos
θ
sin
θ
=
1
−
2
sin
2
θ
cos
2
θ
cos
θ
sin
θ
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Similar questions
Q.
Prove
sin
4
θ
+
cos
4
θ
=
1
−
2
sin
2
θ
cos
2
θ
Q.
Find
tan
3
θ
1
+
tan
2
θ
+
cot
3
θ
1
+
cot
2
θ
−
sec
θ
csc
θ
+
2
sin
θ
cos
θ
Q.
Prove that
tan
2
θ
cos
2
θ
=
1
−
cos
2
θ
Q.
Prove that:
[
1
+
1
tan
2
θ
]
[
1
+
1
cot
2
θ
]
=
1
sin
2
θ
−
sin
4
θ
Q.
Prove that
tan
θ
−
cot
θ
sin
θ
cos
θ
=
tan
2
θ
−
cot
2
θ
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