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Question

Prove : tan3θ1+tan2θ+cot3θ1+cot2θ=12sin2θcos2θsinθcosθ.

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Solution

tan3θ1+tan2θ+cot3θ1+cot2θ
=tan3θsec2θ+cot3θcosec2θ
=sin3θcos3θ1cos2θ+cos3θsin3θ1sin2θ
=sin3θcosθ+cos3θsinθ
=sin4θ+cos4θcosθsinθ
=(sin2θ)2+(cos2θ)2+2sin2θcos2θ2sin2θcos2θcosθsinθ
=(sin2θ+cos2θ)22sin2θcos2θcosθsinθ
=12sin2θcos2θcosθsinθ

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