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Question

Prove:
tanA+secA1tanAsecA+1=1+sinAcosA=secA+tanAQ=cosA1sinA ?

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Solution

(tanAsecA)(sec2Atan2A)tanA+1secA

=(tanAsecA)(1(secAtanA))tanA+1secA

=(tanAsecA)(1secA+tanA)tanA+1secA

=secA+tanA=1cosA+sinAcosA

=1+sinAcosA



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