Prove from the following results that mercury molecules are monoatomic:
(a) 10 g of mercury combine with 0.8 g of oxygen to form an oxide.
(b) 1000 mi. of vapour of Jig at NTP weigh 8.923 g.
(c) The specific heat of the metal is 0.033.

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Solution

(a) Equivalent mass of Hg $= \frac{M a s s o f m e t a l}{M a s s o f o x y g e n} \times 8 = \frac{10}{0.8} \times = 100$
(b) Mass of 1000 mL of Hg vapour at $N T P = 8.923 g$
Mass of 22400 mL of Hg vapour at $N T P = \frac{8.923}{1000} \times 22400 = 199.87 g$ Hence, molecular mass of $H g = 199.87 g$
(c) Approximate atomic mass $= \frac{6.4}{S p . h e a t} = \frac{6.4}{0.033} = 193.93 g$
Valency of $H g = \frac{193.93}{100} ≃ 2$ (nearest whole number)
So, accurate atomic mass $= E q . m a s s \times V a l e n c y$
$= 100 \times 2 = 200 g$
Atomicity $= \frac{M o l . m a s s}{A t . m a s s} = \frac{199.88}{200} ≃ 1$
Hence, mercury molecules are monoatomic.

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combines with oxygen to form

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Prove from the following results that mercury molecules are monoatomic: (a) 10 g of mercury combine with 0.8 g of oxygen to form an oxide. (b) 1000 mi. of vapour of Jig at NTP weigh 8.923 g. (c) The specific heat of the metal is 0.033.

Prove from the following results that mercury molecules are monoatomic:
(a) 10 g of mercury combine with 0.8 g of oxygen to form an oxide.
(b) 1000 mi. of vapour of Jig at NTP weigh 8.923 g.
(c) The specific heat of the metal is 0.033.