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Question

Prove it : ∣ ∣0aba0cbc0∣ ∣=0

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Solution

L.H.S
∣ ∣0aba0cbc0∣ ∣

On expanding w.r.t R1, we get
0(0+c2)a(0+bc)b(ac0)

0abc+abc0

0

R.H.S
Hence, proved.

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