Prove 1 - tan2 A1 - 2 A - 1 - tan A1 - A2

LHS = sec^2Acosec^2A=+sin^2Acos^2A=tan^2A RHS= #160; ( 1 tanA1 cotA )^2 = [ ( 1 tanAtanA 1 ) tanA ]^2 = tan^2A ∴ LHS= RHS ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Basic Trigonometric Identities

Prove 1 + t...

Question

Prove $(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - tan A}{1 - cot A})}^{2}$

Open in App

Solution

Suggest Corrections

Similar questions

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - tan A}{1 - cot A})}^{2} = {tan}^{2} A

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - tan A}{1 - cot A})}^{2} = {tan}^{2} A

(\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}) = {(\frac{1 - tan A}{1 - cot A})}^{2} = {tan}^{2} A

Prove that:
1. $\sqrt{s e c^{2} A + c o s e c^{2} A}$ = tanA + cotA

2. $s i n^{2} A (1 + c o t^{2} A) + c o s^{2} A (1 + t a n^{2} A)$ = 2

$(\frac{1 + t a n^{2} A}{1 + c o t^{2} A}) = (\frac{1 - t a n A}{1 - c o t A})^{2} = t a n^{2} A$

Join BYJU'S Learning Program