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Question

Prove-
(xaxb)a+b×(xbxc)b+c×(xcxa)c+a=1

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Solution

(xab)a+b(xbc)b+c(xca)c+axa2b2xb2c2xc2a2=xa2b2+b2c2+c2a2=x0=1=RHS


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