CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove sin4θ+cos4θ=12sin2θcos2θ

Open in App
Solution

sin4θ+cos4θ
=(sin2θ)2+(cos2θ)2
=(sin2θ+cos2θ)22sin2θcos2θ
=12sin2θcos2θ
=RHS

LHS=RHS

hence proved

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Range of Trigonometric Ratios from 0 to 90
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon