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Question

Prove that:
(1+tanA+cotA)(sinAcosA)=sinAtanAcotAcosA

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Solution

Now,

(1+tanA+cotA)(sinAcosA)

=(sinAcosA)+(tanA.sinAcosA.tanA)+(cotA.sinAcotAcosA)

=(sinAcosA)+(tanA.sinAsinA)+(cotA.sinAcotA.cosA)

=(cosA)+(tanA.sinA)+(cosAcotA.cosA)

=tanA.sinAcosA.cotA.

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