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Question

Prove that 2cosπ13cos9π13+cos3π13+cos5π13=0

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Solution

L.H.S.=2cosπ13cos9π13+cos3π13+cos5π13=cos(9π13+π13)+cos(9π13π13)+cos3π13+cos5π13=cos(10π13)+cos(8π13)+cos3π13+cos5π13=cos(10π13)+cos(8π13)+cos(π10π13)+cos(π8π13)
=cos(10π13)+cos(8π13)cos(10π13)cos(8π13) {cos(πx)=cos x}
=0=R.H.S.

Hence proved.

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