Prove that - 2 sin2 3 -4 - 2 cos2 -4 - 2 2 -3 - 10

2sin ^23π4+2cos ^2π4+2 ^2π3 =2 ( 1√(2) )^2+2 ( 1√(2) )^2+2(2)^2 =1+1+8 =10 ...

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Sum of Trigonometric Ratios in Terms of Their Product

Prove that : ...

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Prove that : $2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10$

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Prove that:

$2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10$

2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

2 {sin}^{2} \frac{5 π}{4} + 2 {cos}^{2} \frac{7 π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

2 {sin}^{2} \frac{3 π}{5} + 2 {cos}^{2} \frac{2 π}{5} + 2 {sec}^{2} \frac{π}{3}

1 + sin x = 2 {cos}^{2} (\frac{π}{4} - \frac{x}{2})

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