Prove that - 2sin 2 - 6 - 2 7- 6 cos 2 - 3 - 3 - 2

LHS=2sin ^2 π6+cosec^2 7π6cos ^2π3 #160; #160; #160; #160; #160; #160; =2×(12)^2+( 2)^2×(12)^2 #160; #160; #160; #160; ...

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General Solution of Trigonometric Equation

Prove that : ...

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Prove that : $2 {sin}^{2} \frac{π}{6} + {csc}^{2} \frac{7 π}{6} {cos}^{2} \frac{π}{3} = \frac{3}{2}$

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{sin}^{2} (\frac{π}{6}) + {cos}^{2} (\frac{π}{3}) - {tan}^{2} (\frac{π}{4}) = - \frac{1}{2}

x

x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{2} \frac{π}{6} sec \frac{π}{3} tan \frac{π}{4}}{c o {sec}^{2} \frac{π}{4} c o {sec} \frac{π}{6}}

(θ + \frac{π}{3}) = cos (θ - \frac{π}{6}),

tan θ + \sqrt{3} = 0

∣ ∣ ∣ 1 - \frac{| sin x |}{1 + | sin x |} ∣ ∣ ∣ \geq \frac{2}{3}

x

{cos}^{2} x + {cos}^{2} (x + \frac{π}{3}) + {cos}^{2} (x - \frac{π}{3}) = \frac{3}{2}

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