Prove that 2tan -1 1 2 -tan -1 4 3

2tan ^ 1 1 2 #160; =tan ^ 1 3 4 #160; Taking RHS =tan ^ 1 1 / 2 #160; +tan ^ 1 1 / 2 #160; =tan ^ 1 ( 1 / 2 + 1 / 2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties Derived from Trigonometric Identities

Prove that ...

Question

Prove that $2 {tan}^{- 1} \frac{1}{2} = {tan}^{- 1} \frac{4}{3}$

Open in App

Solution

Suggest Corrections

Similar questions

2 {tan}^{- 1} (\frac{1}{2}) + {tan}^{- 1} (\frac{1}{7}) = {tan}^{- 1} (\frac{31}{17})

{tan}^{- 1} \frac{1}{4} + {tan}^{- 1} \frac{2}{9} = \frac{1}{2} {cos}^{- 1} \frac{3}{5}

\int \frac{(x^{2} + 1) d x}{(x^{2} + 2) (2 x^{2} + 1)} = \frac{1}{3 \sqrt{(2)}} {{tan}^{- 1} \frac{x}{\sqrt{(2)}} + {tan}^{- 1} x \sqrt{2}} .

Show that 2 $t a n^{- 1} (- 3) = \frac{- π}{2} + t a n^{- 1} (\frac{- 4}{3}) .$

2 {tan}^{- 1} [tan \frac{α}{2} tan (\frac{π}{4} - \frac{β}{2})] = {tan}^{- 1} \frac{sin α c o s β}{cos α + sin β}

Join BYJU'S Learning Program