(20-(3)^1/2-1÷2(2)^1/2×8(6)^1/2)^1/2 = (2)^1/2[(3)^1/2+1]
Find the value of.
(i) (30 + 4−1) × 22 (ii) (2−1 × 4−1) ÷2−2
(iii) (iv) (3−1 + 4−1 + 5−1)0
(v)