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Polynomials

Prove that (2...

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Prove that (2a+3b-4c)^3-8a^3-27b^3+64c^3=6(2a+3b)(3b-4c)(a-2c)

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2 a + 3 b + c = 0

then show that:

8 a^{3} + 27 b^{3} + c^{3} = 18 a b c

Q. Factorise using suitable identity:

{8 a}^{3} - 27 b^{3} - 64 c^{3} - 72 a b c

Q. Find the factors of the polynomial

8 a^{3} + 27 b^{3} + 64 c^{3} - 72 a b c

If $2 a - 3 b = - 1$ and $a b = 12$

then

$8 a^{3} - 27 b^{3} =$

Q. Factorize the given equation :

8 a^{3} + 27 b^{3} + 64 c^{3} - 72 a b c

. And, also find what factors does this equation have?

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