Prove that 3 sin-1-sin-1 3x-4x3-x-1-2-1-2-

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Relation between Trigonometric Ratios

Prove that 3 ...

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Prove that 3 $s i n^{- 1} = s i n^{- 1} (3 x - 4 x^{3}), x ϵ [\frac{- 1}{2}, \frac{1}{2}]$

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3 {sin}^{- 1} x = {sin}^{- 1} (3 x - 4 x^{3}), x ϵ [\begin{matrix} - \frac{1}{2}, \frac{1}{2} \end{matrix}]

t a n^{- 1} \frac{1}{2} - t a n^{- 1} \frac{1}{7} = \frac{π}{4}

s i n^{- 1} x = s i n^{- 1} (3 x - 4 x^{3}), x ϵ [\frac{- 1}{2}, \frac{1}{2}]

Prove the following,

$3 s i n^{- 1} x = s i n^{- 1} (3 x - 4 x^{3}), x ϵ [- \frac{1}{2}, \frac{1}{2}]$

Prove that : $3 s i n^{- 1} x = s i n^{- 1} (3 x - 4 x^{3}), x ϵ [- \frac{1}{2}, \frac{1}{2}] .$

3 {sin}^{- 1} x = {sin}^{- 1} (3 x - 4 x^{3}),

ϵ [- \frac{1}{2}, \frac{1}{2}]

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