Prove that - 61-2- 61-4- 61-8 - -6-

The given series can be written as following #10; #10; #160; S_∞ #10;=6^(11.2·2^2·2^3·2^4· #10;.........2^∞ ) #10; #10; #160; S_∞ # ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of Infinite Terms of a GP

Prove that : ...

Question

Prove that : $6^{1 / 2} \times 6^{1 / 4} \times 6^{1 / 8}$ _________ $\infty = 6$ .

Open in App

Solution

Suggest Corrections

Similar questions

6^{\frac{1}{2}} \times 6^{\frac{1}{4}} \times 6^{\frac{1}{8}} . . . . . \infty = 6

6^{1 / 2} \times 6^{1 / 4} \times 6^{1 / 8} \times \dots \infty

6^{\frac{1}{2}} \times 6^{\frac{1}{4}} \times 6^{\frac{1}{8}} \times 6^{\frac{1}{16}} \times . .

6^{\frac{1}{2}} \times 6^{\frac{1}{2}} \times 6^{\frac{3}{8}} \times 6^{\frac{1}{4}} \times . . . . . . . . .

1 \frac{1}{4} + 1 \frac{5}{9} \times 1 \frac{5}{8} + 6 \frac{1}{2} = ?

Join BYJU'S Learning Program