Let's assume that 6+√2 is a rational number.
So, we can write this number as;
6+√2=ab
Here a and b are two co prime numbers and b ≠ 0.
⇒ √2=ab−6
⇒ √2=a−6bb ----(i)
R.H.S of equation (i) is a rational number, but we know that √2 is an irrational number.
It is not possible.
That means our assumption is wrong.
Hence, 6+√2 is an irrational number.