Let us assume that 7+√2 is a rational number
Then. there exist coprime integers p, q,q≠0 such that
7+√2=pq
=>√2=pq−7
Here, pq−7 is a rational number, but √2 is a irrational number.
But, a irrational cannot be equal to a rational number.This is a contradiction.
Thus, our assumption is wrong.
Therefore 7+√2 is a irrational number.