Prove that 9 P 3 -3- 9 P 2 - 10 P 3-

^9P_3 = 9 !/6 ! ^9P_2 = 9 !/7 ! ^10P_3 = 10 !/7 ! #160; L.H.S = 9 !/6 ! + 3 ×9 !/7 ! = 9× 8× 7 + 3× 9 × 8 = 720 R.H.S = 10 !/7 ! = 10×9× 8 ...

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Rational Expression

Prove that ...

Question

Prove that $^{9} P_{3} + 3 \times^{9} P_{2} =^{10} P_{3}$ .

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p^{2} = a^{2} c o s^{2} θ + b^{2} s i n^{2} θ

P + \frac{d^{2} p}{d θ^{2}} = \frac{a^{2} b^{2}}{p^{3}}

(P_{1})

(P_{2})

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p_{1}, p_{2}, p_{3}

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\frac{1}{p_{1}} + \frac{1}{p_{2}} + \frac{1}{p_{3}} = \frac{1}{r}

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\frac{1}{p_{1}} + \frac{1}{p_{2}} - \frac{1}{p_{3}} = \frac{2 a b}{(a + b + c) △} {cos}^{2} \frac{C}{2}

S (x, t)

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P_{1}, P_{2} a n d P_{3}

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