Prove that:
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$

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Solution

$(a + b)^{2} = (a + b) (a + b)$
$= (a + b) (a) + (a + b) (b)$
$= a^{2} + a b + a b + b^{2}$
$= a^{2} + 2 a b + b^{2}$

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