Given :
ABCD be a cyclic parallelogram.
To prove :ABCD is a rectangle.
A rectangle is a parallelogram with one angle 900
So, we have to prove angle 900
Since ABCD is a paralleogram
∠A=∠C (opposite angle of parallelogram are equal)......................(i)
In cyclic parallelogram ABCD
∠A+∠C=1800 (Sum of opposite angles of a cyclic quadrilateral is 1800)
∠A+∠A=1800 from(i)
2∠A=1800
∠A=18002=900
Hence,
∠A=∠C=90o
Similarly we can prove other two angles are also equal to 90o
Thus, a cyclic parallelogram is rectangle.
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