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Question

Prove that :
∣ ∣0aba0cbc0∣ ∣=0.

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Solution

LHS =∣ ∣0aba0cbc0∣ ∣
Expanding the determinant along R1
=00cc0a0cc0b0cc0
=0a(bc)b(ac)=abcabc
=0=RHS
Hence proved.

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