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Question

Prove that
∣ ∣ ∣bcaa2cabb2abcc2∣ ∣ ∣=∣ ∣ ∣1a2a31b2b31c2c3∣ ∣ ∣

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Solution

∣ ∣ ∣bcaa2cabb2abcc2∣ ∣ ∣
on multiply and divide abc
abcabc∣ ∣ ∣bcaa2cabb2abcc2∣ ∣ ∣
R1,R2,R3
1abc∣ ∣ ∣abca2a3abcb2b3abcc2c3∣ ∣ ∣
Common from C1 to abc
abcabc∣ ∣ ∣1a2a31b2b31c2c3∣ ∣ ∣
∣ ∣ ∣1a2a31b2b31c2c3∣ ∣ ∣.
R.H.S.

1200226_1242814_ans_12bcc6f63504481cb16573bb1b9e1ee0.png

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