Question

Prove that both the roots of the equation $\left(x-a\right)\left(x-b\right)+\left(x-b\right)\left(x-c\right)+\left(x-c\right)\left(x-a\right)=0$ are real but they are equal only when a = b = c.

Answer 1

The quadric equation is

Here,

After simplifying the equation

As we know that

Putting the value of

Since, . So the solutions are real

Let

Then

Thus, the value of

Therefore, the roots of the given equation are real and but they are equal only when,

Hence proved