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Question

Prove that: 1+sin2θcos2θ1+sin2θ+cos2θ=tanθ

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Solution

L.H.S==(1cos2θ)+sin2θ(1cos2θ)+sin2θ=2sin2θ+2sinθcosθ2cos2θ+2sinθcosθ=tanθ= R.H.S


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