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Question

Prove that cosθsinθ+1cosθ+sinθ1=cscθ+cotθ

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Solution


LHS=cosθsinθ+1cosθ+sinθ1

=(cosθsinθ+1)(sinθ+cosθ+1)(sinθ+cosθ1)(sinθ+cosθ+1)


=(1+cosθ)2(sinθ)2(sinθ+cosθ)2(1)2

=1+cos2θ+2cosθsin2θsin2θ+cos2θ+2sinθcosθ1
=1+2cosθ+cos2θ2sinθcosθ

=2cos2θ+2cosθ2sinθcosθ=cosecθ+cotθ=RHS

Hence, Proved

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