Prove that sin 90 o -A cos 90 o -A tan A -cos 2 A

LHS=sin( 90 ^ o A ) #160;cos( 90 ^ o A ) #160; #160;tan A #160; =cos A .sin A #160;sin A #160;cos A #160; #160; =cos A ...

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Sexagesimal System

Prove that ...

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Prove that $\frac{sin (90^{o} - A) cos (90^{o} - A)}{tan A} = {cos}^{2} A$

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