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Question

Prove that (cosecθ+sinθ)(cosecθsinθ)=cot2θ+cos2θ.

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Solution

LHS=(cosecθ+sinθ)(cosecθsinθ)

=cosec2θsin2θ

=(1+cot2θ)(1cos2θ)......(Using Trigonometric Identities)

=cot2θ+cos2θ

=RHS

Hence proved

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