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Question

Prove that cos2{12(BC)}(b+c)2+sin2{12(BC)}(bc)2=1a2

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Solution

L.H.S=cos2(BC2)/k2(sinB+sinC)2+sin2(BC2)/k2(sinBsinC)2
=1/4 k2sin2(B+C2)+1/4k2cos2(B+C2)
={cos2(B+C2)+sin2(B+C2)}+k2(2sinB+C2cosB+C2)2
=1/k2sin2(B+C)=1/k2sin2A=1/a2

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